0=1.2x-0.0234x^2

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Solution for 0=1.2x-0.0234x^2 equation:



0=1.2x-0.0234x^2
We move all terms to the left:
0-(1.2x-0.0234x^2)=0
We add all the numbers together, and all the variables
-(1.2x-0.0234x^2)=0
We get rid of parentheses
0.0234x^2-1.2x=0
a = 0.0234; b = -1.2; c = 0;
Δ = b2-4ac
Δ = -1.22-4·0.0234·0
Δ = 1.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.2)-\sqrt{1.44}}{2*0.0234}=\frac{1.2-\sqrt{1.44}}{0.0468} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.2)+\sqrt{1.44}}{2*0.0234}=\frac{1.2+\sqrt{1.44}}{0.0468} $

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